IPL 2019: Sunrisers Hyderabad defeated Kings XI Punjab by 45 runs

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On Monday, Sunrisers Hyderabad defeated Kings XI Punjab by 45 runs in, to move on to qualify in the playoffs. Legendary spin bowler Rashid Khan’s magic spell was an important contribution after the half-century from openers David Warner, in the best form of Hyderabad win. With this win, Sunrisers have 12 points from 12 matches, and the team is in fourth place. In Punjab, 12 matches out of five wins are 10 points.

The Punjab team made 167 runs in 8 wickets ahead of the target of 213 runs in the match against Rashid Khan (3 for 21 runs), Khalil Ahmed (3 for 40 runs) and Sandeep Sharma (two wickets for 33 runs). Could. Opener KL Rahul scored 79 runs in 56 balls with 5 sixes and 4 fours but the other side did not get any support from the side. Apart from them, no batsman has touched the 30-run mark.

Kings XI Punjab, chasing the target, lost the wicket of aggressive opener Chris Gayle (04) at the score of 11 runs in the third over, which caught Manish Pandey off Khalil’s ball. Rahul and Mayank Agarwal then put the score of 44 runs on a wicket in the Power Play. Rahul hit the ball on Sandeep after hitting the first six of the innings on Khalil.

Agarwal hit six on Rashid, but on the next ball catches Vijay Shankar. He scored 27 runs from 18 balls with two fours and a six. Nicholas Puran (21 runs in 10 balls) came in as soon as they came. After raising sixes on the no ball, Khalil hit two fours and a six in the over, but in the same over Bhuvneshwar took his fantastic catch at long leg.

Rahul hit six and fours in Bhuvneshwar’s overs, while Sandeep hit six, but in spite of that, only 22 runs in two overs. Now Punjab needed 68 runs in three overs. Pardasaran Singh (16), who made his debut, hit six in Bhubaneswar, but 12 runs in the over. In the 19th over of Khalil, Rahul also gave a catch to Williamson, which also ended the true hope of winning Punjab.

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